JEE MAIN - Physics (2021 - 16th March Evening Shift - No. 3)
The following logic gate is equivalent to :
_16th_March_Evening_Shift_en_3_1.png)
NOR Gate
NAND Gate
OR Gate
AND Gate
Giải thích
_16th_March_Evening_Shift_en_3_3.png)
Output of first NAND gate with input A
$$\eqalign{ & = \overline {A.A} \cr & = \overline A + \overline A \cr & = \overline A \cr} $$
Similarly, Output of first NAND gate with input B
$$ = \overline B $$
$$\eqalign{ & {Y_1} = \overline {\overline A .\overline B } \cr & = \overline {\overline A } + \overline {\overline B } \cr & = A + B \cr} $$
$$\eqalign{ & Y = \overline {\left( {A + B} \right).\left( {A + B} \right)} \cr & = \overline {\left( {A + B} \right)} + \overline {\left( {A + B} \right)} \cr & = \overline {\left( {A + B} \right)} \cr} $$
So, given logic gates circuit is a NOR gate.